你好老师，我的这个输入java点击search就会出现下面这个404未找到错误。但是如果我不加后面的search，直接输入/redirect就会进入百度界面。只要加后面的search就错误
package com.bjsxt.servlet;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
/**
* 重定向相应
* response.sendRedirect(URL地址)重定向响应会在响应头中添加一个Location的key对应的value是给定的URL。客户端浏览器在解析响应头后自动向Location中的URL发送请求。
*/
public class RedirectServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
this.doPost(req, resp);
}
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
//进去之后直接会自动请求百度网页并进入
// resp.sendRedirect("https://www.baidu.com");//请求一个URL
req.setCharacterEncoding("utf-8");
//需求：创建一个搜索页面，通过百度搜索引擎完成内容搜索。
String search = req.getParameter("search");
//resp.sendRedirect("https://www.baidu.com/s?ie=utf-8&f=8&rsv_bp=1&rsv_idx=1&tn=baidu&wd=");
resp.sendRedirect("https://www.baidu.com/s?wd="+search);
}
}<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
version="4.0">
<servlet>
<servlet-name>redirectServlet</servlet-name>
<servlet-class>com.bjsxt.servlet.RedirectServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>redirectServlet</servlet-name>
<url-pattern>/redirect</url-pattern>
</servlet-mapping>
</web-app>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<form action="/redirect" method="post">
搜索:<input type="text" name="search" /></br>
<input type="submit" value="Search">
</form>
</body>
</html>
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