cgidao{

    late(lateminute,salary){

        fakuan = ;   (lateminute<){
            System..println();
        }(lateminute<){
            fakuan =;
        }(lateminute<){
            fakuan =;
        }(lateminute<){
            fakuan =() (salary/(*));}{
            fakuan=() (salary*/());
        }
        System..println(+fakuan);

        fakuan;
    }

    main(String[] args) {

(,);
    }

}

老师哪里出错了

老师这个用list()的使用可以讲下吗？？？？？？？？？？？？为啥list(1,2,3)这样会报错??????????

请教老师，你在上课过程中打开的python帮助文档，是哪里的？怎么打开啊？

续7楼问题,解决了该bug后,又出现新的

代码  grant select on sxt.a123 to 'u_sxt'@ with grant option;

报错  1410 - You are not allowed to create a user with GRANT

老师赋值不是n=5；那他（n:5）是什么意思呢

from multiprocessing import Process, Queue

from time import sleep

class MyProcess(Process):

    def __init__(self,name,mq):

        Process.__init__(self)

        self.name = name

        self.mq = mq

    def run(self):

        print(f"Process:{self.name},start")

        print(f"get Data:{self.mq.get()}")

        sleep(3)

        print(f"Process:{self.name},end")

if __name__ == '__main__':

    mq = Queue()

    mq.put("1")

    mq.put("2")

    mq.put("3")

    p_list = []

    for i in range(3):

        p = MyProcess(f"p{i}",mq)

        p_list.append(p)

    for p in p_list:

        p.start()

        #p.join()

为什么要加join，不然会报错，mac

Traceback (most recent call last):

  File "<string>", line 1, in <module>

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 116, in spawn_main

Traceback (most recent call last):

  File "<string>", line 1, in <module>

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 116, in spawn_main

        exitcode = _main(fd, parent_sentinel)exitcode = _main(fd, parent_sentinel)

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 126, in _main

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 126, in _main

    self = reduction.pickle.load(from_parent)

      File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/synchronize.py", line 110, in __setstate__

self = reduction.pickle.load(from_parent)

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/synchronize.py", line 110, in __setstate__

    self._semlock = _multiprocessing.SemLock._rebuild(*state)

FileNotFoundError: [Errno 2] No such file or directory

    self._semlock = _multiprocessing.SemLock._rebuild(*state)

FileNotFoundError: [Errno 2] No such file or directory

Traceback (most recent call last):

  File "<string>", line 1, in <module>

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 116, in spawn_main

    exitcode = _main(fd, parent_sentinel)

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/spawn.py", line 126, in _main

    self = reduction.pickle.load(from_parent)

  File "/Library/Frameworks/Python.framework/Versions/3.10/lib/python3.10/multiprocessing/synchronize.py", line 110, in __setstate__

    self._semlock = _multiprocessing.SemLock._rebuild(*state)

FileNotFoundError: [Errno 2] No such file or directory

老师我的出现了下面的情况？麻烦您帮我看看

这两行是啥意思？？试了一下测试类里面不添加这两行注解启动就会失败 

为什么File.separator不能使用于创建多层目录呢？

package com.changyonglei;

import java.util.Arrays;

//自定义 一个简单的包装类（仅限于联系）
public class MyInteger<toString> {
    private final int value;

    private static MyInteger[] cache;//缓存【-128 ， 127】
    private static final int LOW=-128;
    private static final int HIGH=127;
    static{
        cache=new MyInteger[HIGH-LOW+1];
        for(int i=LOW;i<HIGH;i++){
            cache[i-LOW]=new MyInteger(i);
        }
        System.out.println(Arrays.toString(cache));
    }
    public MyInteger(int value){
        this.value=value;
    }




    public static MyInteger valueOf(int value){
        return new MyInteger(value);
    }
    public int intValue(){
        return value;
    }

    public static void main(String[] args) {
        MyInteger a=new MyInteger(10);
        MyInteger b=MyInteger.valueOf(100);
        int c=b.intValue();
    }
}

老师请问这里面toString不重写为什么返回的是地址呢？这里面调用了Arrays 的toString，已经覆盖了Object的toString了呀 ，应该返回的是字符串值 为什么还是地址呢？我点开Arrays类的toString方法看了也是返回数值中的字符串值呀  ，实在想不明白了！

<!DOCTYPE html>
<html>
 <head>
  <meta charset="UTF-8">
  <title></title>
  <script>
   
   /*function demo1(){
    alert("函数声明一");
   }*/
   /*var demo2=function(){
    alert("函数声明");
   }*/
   var demo3=new Function("alert("函数声明")");
   demo3();
//   demo1();
   function demo4(a,b){
    console.log(a+""+b);
   }
   demo4(1,2)
  </script>
 </head>
 <body>
 </body>
</html>

demo2,dem03,demo4都没输出，是不是和HBuilder,问题。网页左浮点都出不来。

老师为什么我在这里重新设置了文件名为manager.py，也设置了.env文件
安装了那个python-dotenv，还是显示创建不了仓库

我想问的是：protected 的访问对于所有类的解释我不是很理解。

不同包中的子类 都可以进行访问，那所有类又是一个什么样的概念？不是很理解这的概念

public static void closeResourceAll(AutoCloseable... able){
		for (AutoCloseable c : able) {
			if (c!=null) {
				try {
					c.close();
				} catch (Exception e) {
					e.printStackTrace();
				}
			}
		}
	}

老师您好,我可否用如上方法关闭 Statement state, Connection conn, ResultSet rs 等资源. 就不用一个一个去判断关了..

如果不行,还请指点~