"""开发记事本软件菜单"""
from tkinter.filedialog import *
from tkinter.colorchooser import *
class Application(Frame):
def __init__(self,master=None):
super().__init__(master)
self.master=master
self.textpad=None
self.pack()
self.createWidget()
def createWidget(self):
#创建主菜单栏
menubar=Menu(root)
#print(menubar)
#创建子菜单
menuFile=Menu(menubar)
menuEdit=Menu(menubar)
menuHelp=Menu(menubar)
#将子菜单栏添加到主菜单栏
menubar.add_cascade(label="文件(F)",menu=menuFile)
menubar.add_cascade(label="编辑(E)",menu=menuEdit)
menubar.add_cascade(label="帮助(H)",menu=menuHelp)
#给子菜单栏添加菜单项目
menuFile.add_command(label="新建",accelerator="<Ctrl-n>",command=self.newfile)
menuFile.add_command(label="打开",accelerator="<Ctrl-o>",command=self.openfile)
menuFile.add_command(label="保存",accelerator="<Ctrl-s>",command=self.savefile)
menuFile.add_separator()#添加分割线
menuFile.add_command(label="退出",accelerator="<Ctrl-q>",command=self.exit)
#将主菜单栏添加到根窗口
#root.config(menu=menubar)
root["menu"]= menubar
#添加文本框
self.textpad=Text(root)
self.textpad.pack()
#创建上下菜单
self.contextMenu=Menu(root)
self.contextMenu.add_command(label="背景颜色",command=self.openAskColor)
#鼠标右键绑定事件
root.bind("<Button-3>",self.createContextMenu)#通过鼠标右键单击组件而弹出的菜单,需要通过调用post显示鼠标的坐标来显示位置，还有定义方法显示
def newfile(self):
self.textpad.delete("1.0","end")
self.filename=asksaveasfile(title="另存为",initialfile="未命名.txt",filetypes=[("文本文档","*.txt")],
defaultextension=".txt")
self.savefile()
def openfile(self):
self.textpad.delete("1.0","end")#把text控件中的所有内容情空
with askopenfile(title="打开文本文件") as f:
self.textpad.insert(INSERT,f.read())
self.filename=f.name
def savefile(self):
with open(self.filename,"w") as f:
c=self.textpad.get(1.0,END)#获取textpad内的所有内容，
f.write(c)#写到打开的文件中
def exit(self):
root.quit()
def openAskColor(self):
s1=askcolor(color="red",title="选择背景色")
self.textpad.config(bg=s1[1])
def createContextMenu(self,event):
#菜单在鼠标右键单击的坐标处显示
self.contextMenu.post(event.x_root,event.y_root)
if __name__ == '__main__':
root=Tk()
root.geometry("400x300+200+300")
root.title("百战程序员简单的记事本")
app=Application(master=root)
root.mainloop()点击newfile保存后报错是这个，不知道哪里出问题
Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Program Files\Python37\lib\tkinter\__init__.py", line 1705, in __call__
return self.func(*args)
File "C:/Users/Test/Desktop/study/my26.py", line 54, in newfile
self.savefile()
File "C:/Users/Test/Desktop/study/my26.py", line 65, in savefile
with open(self.filename,"w") as f:
TypeError: expected str, bytes or os.PathLike object, not _io.TextIOWrapper
我也是这个路径问题
老师这个....啥意思？..........................................................![$NIB}(E~A`ME5DJO$H8M]6H.png](/ueditor/php/upload/image/20210419/1618838909703202.png "1618838909703202.png")
![P{$M%$W]L0ER7{FHKF5{J5W.png](/ueditor/php/upload/image/20210419/1618838945771046.png "1618838945771046.png")
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